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Thursday, April 29, 2010

#include < stdio.h >
#include < conio.h >

void main()
{

int a[20],c[20],page[20];
int i,j,k,f,n;
int count=0;fault=0,hit=0;
clrscr();
printf("Enter reference string length : ");
scanf("%d",&n);
printf("Enter reference string");
for(i=0;i < n;i++)
   scanf("%d",&page[i]);
printf("Enter frame size ");
scanf("%d",&f);

for(i=0;i < f;i++)
{
   for(j=0;j < fault;j++)
   {
      if(page[i]==a[j])
      {
         hit++;
         c[j]=++count;
         goto xyz;
      }
    }
    a[i]=page[i];
    fault++;
    c[i]=++count;
    xyz: ;
}

Round Robin program using C

#include < stdio.h >
#include < conio.h >

void main()
{

 int  t1=0,wt,twt=0,tat=0,n,i,j,tq,c=0;
 int  bt[10],a[10],f[10],b[10];
 clrscr();
 printf("\n enter no of process: ");
 scanf("%d",&n);

 for(i=0;i < n;i++)
 {
    f[i]=0;    /* indicates process is completed if f[i]==1 */

    a[i]=i+1;    /*  indicates process names    */
 }

 for(i=0;i < n;i++)
 {
     printf("Enter the Burst time of process %d ",i+1);
     scanf("%d",&bt[i]);
     b[i]=bt[i];
 }


 printf("enter the time quantum : ");
 scanf("%d",&tq);

 printf("given burst times are:\n");

 for(i=0;i < n;i++)
 {
    printf("%d\t",bt[i]);
 }
 i=0;

 while(c < n)
 {
    if(bt[i]<=tq && f[i]==0)
    {
    t1=t1+bt[i];
    printf("\n turn around time of p%d is :  %d",a[i],t1);
    wt=t1-b[i];
    printf("\n Waiting time of p%d is     :  %d",a[i],wt);

    tat=tat+t1;
    twt=twt+wt;
    f[i]=1;
    c++;              /* indicating how many processes are completing  */

    }
    else
    {
    if(f[i]==0)
    {
        bt[i]=bt[i]-tq;
        t1=t1+tq;
    }
    }

    i=(i+1)%n;      */    for rotating value of   */
 }

 printf("\n\n Avg turn around time is   :  %d\n",tat/n);

 printf("\n\n Avg Waiting time is       :  %d",twt/n);

 getch();

}





Output:


Enter no of process : 3
Enter the Burst time of process 1 : 20
Enter the Burst time of process 2 : 5
Enter the Burst time of process 3 : 3

Enter time quantum : 4

Given burst times are :
20  5  3

turn around time of p3 is : 11
      Waiting time of p3 is : 8

turn around time of p2 is : 16
      Waiting time of p2 is : 11

turn around time of p1 is : 28
      Waiting time of p1 is :8

 Avg turn arround time is : 18
Avg waiting time is : 9